Wednesday, April 15, 2009

Get file name from a path in VB

One of my friend once asked how to get file name from a path. There're actually a lot of ways to do it. I'll try a simple one, using Split and UBound function.

e.g. the path is C:\Test\DeeperPath\EvenDeeperPath\Test.txt
and we're going to get the file name, i.e. Text.txt

The name of the controls:
textbox : Text1, containing the path

Some things we have to know:
1. To split the path into array: Split(Text1.Text, "\")
We'll get array of string:
Split(Text1.Text, "\")(0) = C:
Split(Text1.Text, "\")(1) = Test
Split(Text1.Text, "\")(2) = DeeperPath
Split(Text1.Text, "\")(3) = EvenDeeperPath
Split(Text1.Text, "\")(4) = Test.txt

2. To get upper bound of an array: UBound(array)

So, to get the file name from a path, we just need a line of code:
Split(Text1.Text, "\")(UBound(Split(Text1.Text, "\")))

The result will be: Test.txt
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2 comments:

  1. hi i am Naveen soni new vb developer give me your gmail id for chat my gmail id is jaihons@gmail.com

    i dont understand this code how it work i founded manny codes on net but not any working i have manny projects to work in vb can you help me for making or solving my problems please reply me?

    ReplyDelete
  2. Hi Naveen, I can not help you making your projects. However, if you have any enquiry, feel free to tell your problem here ^^

    ReplyDelete

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